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Reglarea furnizarii de caldura prin reglare calitativa

Reglarea furnizarii de caldura prin reglare calitativa




Reglarea furnizarii de caldura prin reglare calitativa

Consumatori urbani

t = t 0.5 * * + * ()

T = t + u * ( t - t )



t - temperaturile de intrare , respectiv iesire din corpul de incalzire

t - temperatura interioara

t = 20

= t - t = 85 - 65 = 20

= t - t

= t - t = 20 - ( -18 ) = 38

= - t = [( 85 - 65 ) / 2] - 20 = 55

T - temperatura apei la iesirea din CET

u - coeficient de amestec al apei de retur cu apa de ducere in punctele termice urbane cu hidroelevator cu scopul de a micsora temperatura

m - coeficient care tine seama de tipul corpurilor de incalzire

m = 0.33 - radiatoare din fonta

Pentru consumatori industriali m = 0.25 - pentru registre si serpentine

u = = ( 150 - 85 ) / ( 85 - 65 ) = 3.25

a ) Pentru t = - 18 ; = 38

t = 20 + 0.5 * 20 * ( 38/38 ) + 55 * ( 38/38) 0.751879699 = 85

t = 20 - 0.5 * 20 * ( 38/38 ) + 55 * ( 38/38) 0.751879699 = 65

T = 85 + 3.25 * ( 85 - 65 ) = 150

b ) Pentru t = - 15 ; = 35

t = 20 + 0.5 * 20 * ( 35/38 ) + 55 * ( 35/38) 0.751879699 = 80.9125

t = 20 - 0.5 * 20 * ( 35/38 ) + 55 * ( 35/38) 0.751879699 = 62.492

T = 80.9125 + 3.25 * ( 80.9125 - 62.492 ) = 140.779125

c ) Pentru t = - 10 ; = 30

t = 20 + 0.5 * 20 * ( 30/38 ) + 55 * ( 30/38) 0.751879699 = 73.9386

t = 20 - 0.5 * 20 * ( 30/38 ) + 55 * ( 30/38) 0.751879699 = 58.1492

T = 73.9386 + 3.25 * ( 73.9386 - 58.1492 ) = 125.2541

d ) Pentru t = - 5 ; = 25

t = 20 + 0.5 * 20 * ( 25/38 ) + 55 * ( 25/38) 0.751879699 = 66.72

t = 20 - 0.5 * 20 * ( 25/38 ) + 55 * ( 25/38) 0.751879699 = 53.5667

T = 66.72 + 3.25 * ( 66.72 - 53.5667 ) = 109.46

e ) Pentru t = 0 ; = 20

t = 20 + 0.5 * 20 * ( 20/38 ) + 55 * ( 20/38) 0.751879699 = 59.20315

t = 20 - 0.5 * 20 * ( 20/38 ) + 55 * ( 20/38) 0.751879699 = 48.704

T = 59.20315 + 3.25 * ( 59.20315 - 48.704 ) = 93.325387

f ) Pentru t = 5 ; = 15

t = 20 + 0.5 * 20 * ( 15/38 ) + 55 * ( 15/38) 0.751879699 = 51.28936

t = 20 - 0.5 * 20 * ( 15/38 ) + 55 * ( 15/38) 0.751879699 = 43.3946

T = 51.28936 + 3.25 * ( 51.28936 - 43.3946 ) = 76.9472

g ) Pentru t = 10 ; = 10

t = 20 + 0.5 * 20 * ( 10/38 ) + 55 * ( 10/38) 0.751879699 = 42.789

t = 20 - 0.5 * 20 * ( 10/38 ) + 55 * ( 10/38) 0.751879699 = 37.5258

T = 42.789 + 3.25 * ( 42.789 - 37.5258 ) = 59.89423

Consumatori industriali

T = t 0.5 * ( T1 - T2 ) * () + * ()

t = 16

T1 - T2 = 150 - 70 = 80

= t - t

= t - t = 16 - ( -18 ) = 34

= [( T1 - T2 ) / 2] - t = 94

1 ) m = 0.25 ( registre , serpentine )

a ) t = - 18 ; = 34

T = 16 + 0.5 * 80 * ( 34/34 ) + 94 * ( 34/34) 0.8 = 150

T = 16 - 0.5 * 80 * ( 34/34 ) + 94 * ( 34/34) 0.8 = 70

b ) t = - 15 ; = 31

T = 16 + 0.5 * 80 * ( 31/34 ) + 94 * ( 31/34) 0.8 = 139.774

T = 16 - 0.5 * 80 * ( 31/34 ) + 94 * ( 31/34) 0.8 = 66.8333

c ) t = - 10 ; = 26

T = 16 + 0.5 * 80 * ( 26/34 ) + 94 * ( 26/34) 0.8 = 122.432

T = 16 - 0.5 * 80 * ( 26/34 ) + 94 * ( 26/34) 0.8 = 61.2633

d ) t = - 5 ; = 21

T = 16 + 0.5 * 80 * ( 21/34 ) + 94 * ( 21/34) 0.8 = 104.638

T = 16 - 0.5 * 80 * ( 21/34 ) + 94 * ( 21/34) 0.8 = 55.2264

e ) t = 0 ; = 16

T = 16 + 0.5 * 80 * ( 16/34 ) + 94 * ( 16/34) 0.8 = 86.2538

T = 16 - 0.5 * 80 * ( 16/34 ) + 94 * ( 16/34) 0.8 = 48.60936

f ) t = 5 ; = 11

T = 16 + 0.5 * 80 * ( 11/34 ) + 94 * ( 11/34) 0.8 = 67.0528

T = 16 - 0.5 * 80 * ( 11/34 ) + 94 * ( 11/34) 0.8 = 41.1706

g ) t = 10 ; = 6

T = 16 + 0.5 * 80 * ( 6/34 ) + 94 * ( 6/34) 0.8 = 46.5262

T = 16 - 0.5 * 80 * ( 6/34 ) + 94 * ( 6/34) 0.8 = 32.4086

2 ) m = 0 ( aeroterme )

a ) t = - 18 ; = 34

T = 150 ; T = 70

a ) t = - 15 ; = 31

T = 138.1764 ; T = 65.2353

a ) t = - 10 ; = 26

T = 118.4705 ; T = 57.29415

a ) t = - 5 ; = 21

T = 107.05828 ; T = 49.35

a ) t = 0 ; = 16

T = 150 ; T = 70

a ) t = 5 ; = 11

T = 59.3529 ; T = 33.47058

a ) t = 10 ; = 6

T = 39.64702 ; T = 25.5294

Tabelul 1 URBAN

t

()

t

t

T

-18

38

1

1

85

65

150

35

0.92

0.926157

80.9125

62.492


140.779125

30

0.78

0.823822

73.9386

58.1492

125.2541

25

0.65

0.755777

66.72

53.5667

109.46

20

0.52

0.71174

59.20315

48.704

93.325387

15

0.39

0.49267

51.28936

43.3946

76.9472

10

0.26

0.36692

42.789

39.5258

59.89423

Tabelul 2  m = 0.25 Industriali

t

()

T

T

-18

34

1

1

150

70

31

0.91176

0.919225

139.774

66.8333

26

0.76470

0.81452

122.432

61.2623

21

0.61764

0.74259

104.638

55.2264

16

0.470588

0.70137

86.25638

48.60936

11

0.323529

0.69413

67.0529

41.1706

6

0.17647

0.24965

46.5262

32.4086

Tabelul 3  m = 0 Industriali

t

()

T

T

-18

34

1

1

150

70

31

0.91176

0.91176

138.176

65.235

26

0.76470

0.76470

118.4705

57.294

21

0.61764

0.61764

98.764

49.35

16

0.470588

0.470588

79.0588

41.411

11

0.323529

0.323529

59.3529

33.47

6

0.17647

0.17647

39.64702

25.52

Completarea graficului de reglare a furnizarii de caldura pentru calcul hidraulic

Alegem curba graficului industrial

T1N = 150

t1N = 85

t2N = 65

T1` = 70

t1` = 48



t2` = 42

T1`` 94.5

t1`` = 60

t2`` = 49

Pentru temperatura exterioara de calcul tec = - 18 corespunde tem`` =

tem`` - temp. apei coresp. temperaturii medii de lunga durata

A ) q = k * s * = k * s *

T1 + T2 = T1u + T2x

T2x = T2 - ( T1u - T1 )

m = 0.25

a1 ) te = - 18

T2x = T2ind - ( T1u - T1ind ) = 70 - ( 150 - 150 ) = 70

a2 ) te = - 15

T2x = 66.833 - ( 140.779 - 139.774 ) = 65.828

a3 ) te = - 10

T2x = 61.2623 - ( 125.254 - 122.432 ) = 58.44

a4 ) te = - 5

T2x = 55.2264 - ( 109.46 - 104.638 ) = 50.404

a5 ) te = 0

T2x = 48.6093 - ( 93.325 - 86.256 ) = 41.539

a6 ) te = 5

T2x = 41.1706 - ( 76.9472 - 67.053 ) = 31.276

a7 ) te = 10

T2x = 32.4086 - ( 59.894 - 46.526 ) = 19.040

B ) q = GC ( T1 - T2 ) = GxC (T1u - T2x )

Gx / G = ( T1 - T2 ) / (T1u - T2x )

m = 0.25

b1 ) te = - 18

Gx / G = ( T1 - T2 ) / (T1u - T2x ) = ( 150 - 70 ) / ( 150 - 70 ) = 1

b2 ) te = - 15

Gx / G = ( 139.774 - 66.8333 ) / ( 140.779 - 65.828 ) = 0.9731

b3 ) te = - 10

Gx / G = ( 122.432 - 61.2623 ) / ( 125.254 - 58.440 ) = 0.9155

b4 ) te = - 5

Gx / G = ( 104.638 - 55.2264 ) / ( 109.46 - 50.404 ) = 0.8366

b5 ) te = 0

Gx / G = ( 80.256 - 48.609 ) / ( 93.325 - 41.5393 ) = 0.7269

b6 ) te = 5

Gx / G = ( 67.0529 - 41.1706 ) / ( 76.947 - 31.276 ) = 0.5667

b7 ) te = 10

Gx / G = ( 46.5262 - 32.408 ) / ( 59.894 - 19.040 ) = 0.34557

m = 0

a1 ) te = - 18

T2x = T2 - ( T1u - T1 ) = 70 - ( 150 - 150 ) = 70

a2 ) te = - 15

T2x = 65.235 - ( 140.779 - 138.176 ) = 62.632

a3 ) te = - 10

T2x = 57.294 - ( 125.254 - 118.470 ) = 50.51

a4 ) te = - 5

T2x = 49.35 - ( 109.46 - 98.764 ) = 38.654

a5 ) te = 0

T2x = 41.4117 - ( 93.325 - 79.0588 ) = 27.145

a6 ) te = 5

T2x = 33.470 - ( 76.9472 - 59.3529 ) = 15.875

a7 ) te = 10

T2x = 25.529 - ( 59.894 - 39.647 ) = 5.282

q = GC ( T1 - T2 ) = GxC (T1u - T2x )

Gx / G = ( T1 - T2 ) / (T1u - T2x )

m = 0

b1 ) te = - 18

Gx / G = ( T1 - T2 ) / (T1u - T2x ) = ( 150 - 70 ) / ( 150 - 70 ) = 1

b2 ) te = - 15

Gx / G = ( 138.176 - 65.235 ) / ( 140.779 - 62.632 ) = 0.93

b3 ) te = - 10

Gx / G = ( 118.47 - 57.294 ) / ( 125.254 - 50.51 ) = 0.818

b4 ) te = - 5

Gx / G = ( 98.764 - 49.35 ) / ( 109.46 - 38.65 ) = 0.697

b5 ) te = 0

Gx / G = ( 70.058 - 41.411 ) / ( 93.325 - 27.145 ) = 0.0.568

b6 ) te = 5

Gx / G = ( 59.352 - 33.47 ) / ( 76.947 - 15.875 ) = 0.423

b7 ) te = 10

Gx / G = ( 39.647 - 25.529 ) / ( 59.894 - 5.282 ) = 0.258

Tabel 3 Calculul sarcinii termice la CET N = 16

 

Denumirea

Qinc.

Qmed.ac

Qtotal 1 sc

Qtotal

URBAN

MW

MW

MW

MW

SC1-SC4

SC5-SC8

SC9-SC12

SC13-SC18

TOTAL URBAN

INDUSTRIAL

PTI1

PTI2

PTI3

TOTAL INDUSTRIAL

TOTAL ORAS

Calculul hidraulic

Qtot.CET = Qtot ORAS + QR

SC 1

I . Qinc = 5.6 MW

II . Qmedacm = 1.12 MW



III . G inc = 56.60 t/h

IV . Gmedacm = 6.76 t/h

Gtot = G inc + Gmedacm = 63.36 t/h

III . G inc = Qinc/ [ c*( T1 - t2 ) ] = 5.6 * 3600 / 356.15 = 56.60 t/h

IV . Gmedacm = QII medacm / [ c* ( T``1 - t``2 ) ]

QII medacm = Qmedacm * ( tac - tint ) / ( tac - tar ) = 1.12 * ( [ 60 - ( 49 - 5 ) ] / ( 60 - 10 ) =

= 0.358

Gmedacm = ( 0.358 * 3600 ) / [ 4.19 * ( 94.5 - 49 ) ] = 6.76 t/h

SC 2

I . Qinc = 5.6 MW

II . Qmedacm = 1.12 MW

III . G inc = 56.60 t/h

IV . Gmedacm = 6.76 t/h

Gtot = G inc + Gmedacm = 63.36 t/h

SC 3

I . Qinc = 5.6 MW

II . Qmedacm = 1.12 MW

III . G inc = 56.60 t/h

IV . Gmedacm = 6.76 t/h

Gtot = G inc + Gmedacm = 63.36 t/h

SC 4

I . Qinc = 5.6 MW

II . Qmedacm = 1.12 MW

III . G inc = 56.60 t/h

IV . Gmedacm = 6.76 t/h

Gtot = G inc + Gmedacm = 63.36 t/h

SC 5

I . Qinc = 6.6 MW

II . Qmedacm = 1.32 MW

III . G inc = 66.72 t/h

IV . Gmedacm = 7.97 t/h

Gtot = G inc + Gmedacm = 74.69 t/h

III . G inc = Qinc/ [ c*( T1 - t2 ) ] = 6.6 * 3600 / 4.19*( 150 - 65 ) = 66.72 t/h

IV . Gmedacm = QII medacm / [ c* ( T``1 - t``2 ) ]

QII medacm = Qmedacm * ( tac - tint ) / ( tac - tar ) = 1.32 * ( [ 60 - ( 49 - 5 ) ] / ( 60 - 10 ) =

= 0.422

Gmedacm = ( 0.422 * 3600 ) / [ 4.19 * ( 94.5 - 49 ) ] = 7.97 t/h

SC 6

I . Qinc = 6.6 MW

II . Qmedacm = 1.32 MW

III . G inc = 66.72 t/h

IV . Gmedacm = 7.97 t/h

Gtot = G inc + Gmedacm = 74.69 t/h

SC 7

I . Qinc = 6.6 MW

II . Qmedacm = 1.32 MW

III . G inc = 66.72 t/h

IV . Gmedacm = 7.97 t/h

Gtot = G inc + Gmedacm = 74.69 t/h

SC 8

I . Qinc = 6.6 MW

II . Qmedacm = 1.32 MW

III . G inc = 66.72 t/h

IV . Gmedacm = 7.97 t/h

Gtot = G inc + Gmedacm = 74.69 t/h

SC 9

I . Qinc = 7.6 MW

II . Qmedacm = 1.52 MW

III . G inc = 76.82 t/h

IV . Gmedacm = 9.18 t/h

Gtot = G inc + Gmedacm = 86.004 t/h

III . G inc = Qinc/ [ c*( T1 - t2 ) ] = 7.6 * 3600 / 4.19*( 150 - 65 ) = 76.82 t/h

IV . Gmedacm = QII medacm / [ c* ( T``1 - t``2 ) ]

QII medacm = Qmedacm * ( tac - tint ) / ( tac - tar ) = 1.52 * ( [ 60 - ( 49 - 5 ) ] / ( 60 - 10 ) =

= 0.486

Gmedacm = ( 0.486 * 3600 ) / [ 4.19 * ( 94.5 - 49 ) ] = 9.184 t/h

SC 10

I . Qinc = 7.6 MW

II . Qmedacm = 1.52 MW

III . G inc = 76.82 t/h

IV . Gmedacm = 9.18 t/h

Gtot = G inc + Gmedacm = 86.004 t/h

SC 11

I . Qinc = 7.6 MW

II . Qmedacm = 1.52 MW

III . G inc = 76.82 t/h

IV . Gmedacm = 9.18 t/h

Gtot = G inc + Gmedacm = 86.004 t/h

SC 12

I . Qinc = 7.6 MW

II . Qmedacm = 1.52 MW

III . G inc = 76.82 t/h

IV . Gmedacm = 9.18 t/h

Gtot = G inc + Gmedacm = 86.004 t/h

SC 13

I . Qinc = 8.6 MW

II . Qmedacm = 1.72 MW

III . G inc = 86.93 t/h

IV . Gmedacm = 10.38 t/h

Gtot = G inc + Gmedacm = 97.31 t/h

III . G inc = Qinc/ [ c*( T1 - t2 ) ] = 8.6 * 3600 / 4.19*( 150 - 65 ) = 86.93 t/h

IV . Gmedacm = QII medacm / [ c* ( T``1 - t``2 ) ]

QII medacm = Qmedacm * ( tac - tint ) / ( tac - tar ) = 1.72 * ( [ 60 - ( 49 - 5 ) ] / ( 60 - 10 ) =

= 0.550

Gmedacm = ( 0.550 * 3600 ) / [ 4.19 * ( 94.5 - 49 ) ] = 10.38 t/h

SC 14

I . Qinc = 8.6 MW

II . Qmedacm = 1.72 MW

III . G inc = 86.93 t/h

IV . Gmedacm = 10.38 t/h

Gtot = G inc + Gmedacm = 97.31 t/h

SC 15

I . Qinc = 8.6 MW

II . Qmedacm = 1.72 MW

III . G inc = 86.93 t/h

IV . Gmedacm = 10.38 t/h

Gtot = G inc + Gmedacm = 97.31 t/h

SC 16

I . Qinc = 8.6 MW

II . Qmedacm = 1.72 MW

III . G inc = 86.93 t/h

IV . Gmedacm = 10.38 t/h

Gtot = G inc + Gmedacm = 97.31 t/h

SC 17

I . Qinc = 8.6 MW

II . Qmedacm = 1.72 MW

III . G inc = 86.93 t/h

IV . Gmedacm = 10.38 t/h

Gtot = G inc + Gmedacm = 97.31 t/h

SC 18

I . Qinc = 8.6 MW

II . Qmedacm = 1.72 MW

III . G inc = 86.93 t/h

IV . Gmedacm = 10.38 t/h

Gtot = G inc + Gmedacm = 97.31 t/h

PTI 1

I . Qinc = 38.2 MW

II . Qmedacm = 1.91 MW

III . G inc = 410.26 t/h

IV . Gmedacm = 46.88 t/h

Gtot = G inc + Gmedacm = 457.147 t/h

G inc = Qinc/ [ c*( T1 - T2 ) ] = 38.2 * 3600 / 4.19*( 150 - 70 ) = 410.26 t/h

Gmedacm = Qmedacm / [ c* ( T`1 - t 3 ) ] = ( 1.91 * 3600 ) / [ 4.19 * ( 70 - 35 ) ] = 46.88 t/h

PTI 2

I . Qinc = 56.6 MW

II . Qmedacm = 2.83 MW

III . G inc = 607.87 t/h

IV . Gmedacm = 69.47 t/h

Gtot = G inc + Gmedacm = 677.34 t/h

G inc = Qinc/ [ c*( T1 - T2 ) ] = 56.6 * 3600 / 4.19*( 150 - 70 ) = 607.87 t/h

Gmedacm = Qmedacm / [ c* ( T`1 - t 3 ) ] = ( 2.83 * 3600 ) / [ 4.19 * ( 70 - 35 ) ] = 69.47 t/h

PTI 3

I . Qinc = 18.2 MW

II . Qmedacm = 0.91 MW

III . G inc = 195.46 t/h

IV . Gmedacm = 22.338 t/h

Gtot = G inc + Gmedacm = 217.798 t/h

G inc = Qinc/ [ c*( T1 - T2 ) ] = 18.2 * 3600 / 4.19*( 150 - 70 ) = 195.46 t/h

Gmedacm = Qmedacm / [ c* ( T`1 - t 3 ) ] = ( 0.91 * 3600 ) / [ 4.19 * ( 70 - 35 ) ] = 22.338 t/h

Calculul hidraulic

- tronsoane -

5 - SC 1

1 ) Qt = Qinc + Qmedacm = 5.6 + 1.12 = 6.72 MW

2 ) Gt = Ginc + Gmedacm = 63.36 t/h

3 ) L = 300 m

5 - SC 17

1 ) Qt = Qinc + Qmedacm = 8.6 + 1.72 = 10.32 MW

2 ) Gt = Ginc + Gmedacm = 97.31 t/h

3 ) L = 200 m

5 - SC 2

1 ) Qt = Qinc + Qmedacm = 5.6 + 1.12 = 6.72 MW

2 ) Gt = Ginc + Gmedacm = 63.36 t/h

3 ) L = 100 m

4 - 5

1 ) Qt = 2 * 6.72 + 10.32 = 23.76 MW

2 ) Gt = 2 * 63.36 + 97.31 = 224.03 t/h

3 ) L = 600 m

6 - SC 2

1 ) Qt = Qinc + Qmedacm = 5.6 + 1.12 = 6.72 MW

2 ) Gt = Ginc + Gmedacm = 63.36 t/h

3 ) L = 200 m

6 - SC 4

1 ) Qt = Qinc + Qmedacm = 5.6 + 1.12 = 6.72 MW

2 ) Gt = Ginc + Gmedacm = 63.36 t/h

3 ) L = 300 m

4 - 6

1 ) Qt = 2 * 6.72 = 13.44 MW

2 ) Gt = 2 * 63.36 = 126.72 t/h

3 ) L = 200 m

3 - 4

1 ) Qt = Q 4-5 + Q 4-6 = 23.76 + 13.44 = 37.2 MW

2 ) Gt = 224.03 = 126.72 = 350.75 t/h

3 ) L = 600 m

7 - SC 6

1 ) Qt = Qinc + Qmedacm = 6.6 + 1.32 = 7.92 MW

2 ) Gt = Ginc + Gmedacm = 74.69 t/h

3 ) L = 200 m

7 - SC 5

1 ) Qt = Qinc + Qmedacm = 6.6 + 1.32 = 7.92 MW

2 ) Gt = Ginc + Gmedacm = 74.69 t/h

3 ) L = 200 m

7 - SC 7

1 ) Qt = Qinc + Qmedacm = 6.6 + 1.32 = 7.92 MW

2 ) Gt = Ginc + Gmedacm = 74.69 t/h

3 ) L = 200 m

7 - 3

1 ) Qt = 3 * 7.92 = 23.76 MW

2 ) Gt = 3 * 74.69 = 224.07 t/h

3 ) L = 200 m

2 - 3

1 ) Qt = Q 3 - 4 + Q 3 - 7 = 37.2 + 23.76 = 60.96 MW

2 ) Gt = G 3 - 4 + G 3 - 7 = 350.75 + 224.07 = 574.82 t/h

3 ) L = 600 m

8 - PTI 1

1 ) Qt = Qinc + Qmedacm = 38.2 + 1.91 = 40.11 MW

2 ) Gt = Ginc + Gmedacm = 457.147 t/h

3 ) L = 100 m

8 - PTI 2

1 ) Qt = Qinc + Qmedacm = 56.6 + 2.83 = 59.43 MW

2 ) Gt = Ginc + Gmedacm = 677.34 t/h

3 ) L = 100 m

2 - 8

1 ) Qt = 40.11 + 59.43 = 99.54 MW

2 ) Gt = 457.147 + 677.34 = 1134.48 t/h

3 ) L = 200 m

1 - 2

1 ) Qt = Q 2 - 8 + Q 2 - 3 = 60.96 + 99.54 = 160.5 MW

2 ) Gt = G 2 - 8 + G 2 - 3 = 574.82 + 1134.48 = 1709.309 t/h

3 ) L = 500 m

13 - SC 8

1 ) Qt = Qinc + Qmedacm = 6.6 + 1.32 = 7.92 MW

2 ) Gt = Ginc + Gmedacm = 74.69 t/h

3 ) L = 200 m

13 - SC 9

1 ) Qt = Qinc + Qmedacm = 7.6 + 1.52 = 9.12 MW

2 ) Gt = Ginc + Gmedacm = 86.004 t/h

3 ) L = 100 m

13 - 11

1 ) Qt = 7.92 + 9.12 = 17.04 MW

2 ) Gt = 74.69 + 86.004 = 160.69 t/h

3 ) L = 1000 m

15 - SC 18

1 ) Qt = Qinc + Qmedacm = 8.6 + 1.72 = 10.32 MW

2 ) Gt = Ginc + Gmedacm = 97.31 t/h

3 ) L = 100 m

15 - SC 10

1 ) Qt = Qinc + Qmedacm = 7.6 + 1.52 = 9.12 MW

2 ) Gt = Ginc + Gmedacm = 86.004 t/h

3 ) L = 100 m

14 - 15

1 ) Qt = 10.32 + 9.12 = 19.44 MW

2 ) Gt = 97.31 + 86.004 = 183.31 t/h

3 ) L = 100 m

14 - SC 11

1 ) Qt = Qinc + Qmedacm = 7.6 + 1.52 = 9.12 MW

2 ) Gt = Ginc + Gmedacm = 86.004 t/h

3 ) L = 100 m

11 - 14

1 ) Qt = 19.44 + 9.12 = 28.56 MW

2 ) Gt = 183.31 + 86.004 = 269.32 t/h

3 ) L = 200 m

10 - 11

1 ) Qt = Q 11 - 14 + Q 11 - 13 = 28.56 + 17.04 = 45.6 MW

2 ) Gt = G 11 - 14 + G 11 - 13 = 269.32 + 160.69 = 430.01 t/h

3 ) L = 600 m

16 - SC 16

1 ) Qt = Qinc + Qmedacm = 8.6 + 1.72 = 10.32 MW

2 ) Gt = Ginc + Gmedacm = 97.31 t/h

3 ) L = 200 m

16 - SC 15

1 ) Qt = Qinc + Qmedacm = 8.6 + 1.72 = 10.32 MW

2 ) Gt = Ginc + Gmedacm = 97.31 t/h

3 ) L = 100 m

10 - 16

1 ) Qt = 2 * 10.32 = 20.64 MW

2 ) Gt = 2 * 97.31 = 194.62 t/h

3 ) L = 200 m

9 - 10

1 ) Qt = 20.64 + 45.6 = 66.24 MW

2 ) Gt = 194.62 + 430.01 = 624.63 t/h

3 ) L = 700 m

17 - SC 12

1 ) Qt = Qinc + Qmedacm = 7.6 + 1.52 = 9.12 MW

2 ) Gt = Ginc + Gmedacm = 86.004 t/h

3 ) L = 100 m

17 - SC 13

1 ) Qt = Qinc + Qmedacm = 8.6 + 1.72 = 10.32 MW

2 ) Gt = Ginc + Gmedacm = 97.31 t/h

3 ) L = 200 m

18 - 17

1 ) Qt = 9.12 + 10.32 = 19.44 MW

2 ) Gt = 86.004 + 97.31 = 183.31 t/h

3 ) L = 100 m

18 - SC 14

1 ) Qt = Qinc + Qmedacm = 8.6 + 1.72 = 10.32 MW

2 ) Gt = Ginc + Gmedacm = 97.31 t/h

3 ) L = 300 m

9 - 18

1 ) Qt = 10.32 + 19.44 = 29.76 MW

2 ) Gt = 97.31 + 183.31= 280.62 t/h

3 ) L = 500 m

9 - PTI 3

1 ) Qt = Qinc + Qmedacm = 18.2 + 0.91 = 19.11 MW

2 ) Gt = Ginc + Gmedacm = 217.798 t/h

3 ) L = 200 m

1 - 9

1 ) Qt = 19.11 + 29.76 + 66.24 = 115.11 MW

2 ) Gt = 217.798 + 280.62 + 624.63 = 1123.048 t/h

3 ) L = 400 m

CET - 1

1 ) Qt = 160.5 + 115.11 = 275.61 MW

2 ) Gt = 1709.307 + 1123.048 = 2832.35 t/h

3 ) L = 2800 m

UNIVERSITATEA TEHNICA DE CONSTRUCTII BUCURESTI

FACULTATEA DE INSTALATII


Radu Daciana

Seria B An 5 Grupa 5






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